Cleaner implementation of Domain.__or__() (seems slower?)

[linpy.git] / examples / squares.py

diff --git a/examples/squares.py b/examples/squares.py
index 1df6e3d..98e2ca8 100755 (executable)
--- a/examples/squares.py
+++ b/examples/squares.py
@@ -1,23 +1,8 @@
 #!/usr/bin/env python3
 
 #!/usr/bin/env python3
 

-"""
-    This file is part of Linpy.
-
-    Linpy is free software: you can redistribute it and/or modify
-    it under the terms of the GNU General Public License as published by
-    the Free Software Foundation, either version 3 of the License, or
-    (at your option) any later version.
-
-    Linpy is distributed in the hope that it will be useful,
-    but WITHOUT ANY WARRANTY; without even the implied warranty of
-    MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
-    GNU General Public License for more details.
-
-    You should have received a copy of the GNU General Public License
-    along with Linpy.  If not, see <http://www.gnu.org/licenses/>.
-"""
-
-from pypol import *
+from linpy import *
+import matplotlib.pyplot as plt
+from matplotlib import pylab

 
 a, x, y, z = symbols('a x y z')
 
 
 a, x, y, z = symbols('a x y z')
 


@@ -30,7 +15,6 @@ sq6 = Le(1, x) & Le(x, 2) & Le(1, y) & Le(y, 3)
 sq7 = Le(0, x) & Le(x, 2) & Le(0, y) & Eq(z, 2) & Le(a, 3)
 p = Le(2*x+1, y) & Le(-2*x-1, y) & Le(y, 1)
 
 sq7 = Le(0, x) & Le(x, 2) & Le(0, y) & Eq(z, 2) & Le(a, 3)
 p = Le(2*x+1, y) & Le(-2*x-1, y) & Le(y, 1)
 

-

 universe = Polyhedron([])
 q = sq1 - sq2
 e = Empty
 universe = Polyhedron([])
 q = sq1 - sq2
 e = Empty


@@ -77,21 +61,27 @@ print('lexographic max of sq2:', sq2.lexmax()) #test lexmax()
 print()
 print('Polyhedral hull of sq1 + sq2 is:', q.aspolyhedron()) #test polyhedral hull
 print()
 print()
 print('Polyhedral hull of sq1 + sq2 is:', q.aspolyhedron()) #test polyhedral hull
 print()

-print('is sq1 bounded?', sq1.isbounded()) #unbounded should return True
+print('is sq1 bounded?', sq1.isbounded()) #bounded should return True

 print('is sq5 bounded?', sq5.isbounded()) #unbounded should return False
 print()
 print('sq6:', sq6)
 print('is sq5 bounded?', sq5.isbounded()) #unbounded should return False
 print()
 print('sq6:', sq6)

-print('sq6 simplified:', sq6.sample())
-print()
-print(universe.project([x]))
-print('sq7 with out constraints involving y and a', sq7.project([a, z, x, y])) #drops dims that are passed
+print('sample Polyhedron from sq6:', sq6.sample())

 print()
 print()

-print('sq1 has {} parameters'.format(sq1.num_parameters()))
-print()
-print('does sq1 constraints involve x?', sq1.involves_dims([x]))
+print('sq7 with out constraints involving y and a', sq7.project([a, z, x, y])) 

 print()
 print('the verticies for s are:', p.vertices())
 print()
 print('the verticies for s are:', p.vertices())

-print()
-print(p.plot())

 
 

-# Copyright 2014 MINES ParisTech  
+
+# plotting the intersection of two squares
+square1 = Le(0, x) & Le(x, 2) & Le(0, y) & Le(y, 2)
+square2 = Le(1, x) & Le(x, 3) & Le(1, y) & Le(y, 3)
+
+fig = plt.figure()
+plot = fig.add_subplot(1, 1, 1, aspect='equal')
+square1.plot(plot, facecolor='red', alpha=0.3)
+square2.plot(plot, facecolor='blue', alpha=0.3)
+
+squares = Polyhedron(square1 + square2)
+squares.plot(plot, facecolor='blue', alpha=0.3)
+
+pylab.show()